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受欢迎的代数 >

(λ^2-14)-20=λ

解答

(λ^{2} - 14) - 20 = λ

解答

λ = \frac{1 + 137}{2}, λ = \frac{1 - 137}{2}

+1

十进制

λ = 6.35234 \dots, λ = - 5.35234 \dots

求解步骤

(λ^{2} - 14) - 20 = λ

整理后得

λ^{2} - 34 = λ

将

λ

para o lado esquerdo

λ^{2} - 34 - λ = 0

改写成标准形式

a x^{2} + b x + c = 0

λ^{2} - λ - 34 = 0

使用求根公式求解

λ_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 34 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 34) = 137

λ_{1, 2} = \frac{- ( - 1 ) \pm 137}{2 \cdot 1}

将解分隔开

λ_{1} = \frac{- ( - 1 ) + 137}{2 \cdot 1}, λ_{2} = \frac{- ( - 1 ) - 137}{2 \cdot 1}

λ = \frac{- ( - 1 ) + 137}{2 \cdot 1} : \frac{1 + 137}{2}

λ = \frac{- ( - 1 ) - 137}{2 \cdot 1} : \frac{1 - 137}{2}

二次方程组的解是:

λ = \frac{1 + 137}{2}, λ = \frac{1 - 137}{2}

作图

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