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受欢迎的代数 >

60t+1.05t^2=800

解答

60 t + 1.05 t^{2} = 800

解答

t = \frac{40 ( 435 - 15 )}{21}, t = - \frac{40 ( 15 + 435 )}{21}

+1

十进制

t = 11.15553 \dots, t = - 68.29838 \dots

求解步骤

60 t + 1.05 t^{2} = 800

在两边乘以

100

6000 t + 105 t^{2} = 80000

将

80000

para o lado esquerdo

6000 t + 105 t^{2} - 80000 = 0

改写成标准形式

a x^{2} + b x + c = 0

105 t^{2} + 6000 t - 80000 = 0

使用求根公式求解

t_{1, 2} = \frac{- 6000 \pm 600 0 ^{2} - 4 \cdot 105 ( - 80000 )}{2 \cdot 105}

600 0^{2} - 4 \cdot 105 (- 80000) = 400435

t_{1, 2} = \frac{- 6000 \pm 400 435}{2 \cdot 105}

将解分隔开

t_{1} = \frac{- 6000 + 400 435}{2 \cdot 105}, t_{2} = \frac{- 6000 - 400 435}{2 \cdot 105}

t = \frac{- 6000 + 400 435}{2 \cdot 105} : \frac{40 ( 435 - 15 )}{21}

t = \frac{- 6000 - 400 435}{2 \cdot 105} : - \frac{40 ( 15 + 435 )}{21}

二次方程组的解是:

t = \frac{40 ( 435 - 15 )}{21}, t = - \frac{40 ( 15 + 435 )}{21}

作图

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