(s+4)(s-3)<= 0

Lösung

(s + 4) (s - 3) \leq 0

- 4 \leq s \leq 3

Intervall-Notation

[- 4, 3]

Schritte zur Lösung

(s + 4) (s - 3) \leq 0

Identifiziere die Intervalle

- 4 \leq s \leq 3

25 n^{2} - 1 = 0

2 x^{2} + 5 x - 10 = 0

5 x - 7 (- x + 2) = 58

f a c t or 16 k^{2} - 1

x^{2} + 6 x - 19 = 0