e^{x^2+2}=57

Lösung

e^{x^{2} + 2} = 57

x = ln (57) - 2, x = - ln (57) - 2

Dezimale

x = 1.42935 \dots, x = - 1.42935 \dots

Schritte zur Lösung

e^{x^{2} + 2} = 57

Wende Exponentenregel an

x^{2} + 2 = ln (57)

Löse

x^{2} + 2 = ln (57) : x = ln (57) - 2, x = - ln (57) - 2

x = ln (57) - 2, x = - ln (57) - 2

9^{x} = 2 7^{2 - 2 x}

e^{x - 1} = e^{2 (x + 1)}

4^{x - 1} + 2^{x + 2} = 48

(\frac{1}{2})^{3 a} = 2^{3 a + 3}

2^{x - 2} = \frac{8}{2 ^{x - 3}}