8^x=4^{x+1}

Lösung

8^{x} = 4^{x + 1}

x = 2

Schritte zur Lösung

8^{x} = 4^{x + 1}

Wende Exponentenregel an

3 x = 2 (x + 1)

Löse

3 x = 2 (x + 1) : x = 2

x = 2

6^{2 x - 6} = 3 6^{3 x - 5}

2^{x} - x^{2} = 0

(0.5)^{\frac{9900}{x}} = 0.3

5^{2 x + 1} = 6 (5^{x}) - 1

3^{4 - x^{2}} = \frac{1}{9}