2^{x-1}=3^{x+1}

Lösung

2^{x - 1} = 3^{x + 1}

x = \frac{ln ( 6 )}{ln ( 2 ) - ln ( 3 )}

Dezimale

x = - 4.41902 \dots

Schritte zur Lösung

2^{x - 1} = 3^{x + 1}

Wende Exponentenregel an

(x - 1) ln (2) = (x + 1) ln (3)

Löse

(x - 1) ln (2) = (x + 1) ln (3) : x = \frac{ln ( 6 )}{ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 6 )}{ln ( 2 ) - ln ( 3 )}

8^{2 x} - 10 (8^{x}) + 16 = 0

1 6^{x} = \frac{1}{8}

e^{7 x} = 7 e^{x}

e^{2 x} + e^{x} = 6

e^{x + 2} = (e^{x - 1})^{2}