6^{3x+1}=2^{2x-3}

Lösung

6^{3 x + 1} = 2^{2 x - 3}

x = - \frac{ln ( 48 )}{ln ( 54 )}

Dezimale

x = - 0.97047 \dots

Schritte zur Lösung

6^{3 x + 1} = 2^{2 x - 3}

Wende Exponentenregel an

(3 x + 1) ln (6) = (2 x - 3) ln (2)

Löse

(3 x + 1) ln (6) = (2 x - 3) ln (2) : x = - \frac{ln ( 48 )}{ln ( 54 )}

x = - \frac{ln ( 48 )}{ln ( 54 )}

10 0^{x} = 1

3^{(x - 4)} = 7

(\frac{1}{4})^{x + 1} = 32

3^{x} = 24

\frac{4 ^{6}}{4 ^{x}} = 4^{0}