2^{(x-2)(2x+1)}=1

Lösung

2^{(x - 2) (2 x + 1)} = 1

x = 2, x = - \frac{1}{2}

Dezimale

x = 2, x = - 0.5

Schritte zur Lösung

2^{(x - 2) (2 x + 1)} = 1

Wende Exponentenregel an

(x - 2) (2 x + 1) ln (2) = ln (1)

Löse

(x - 2) (2 x + 1) ln (2) = ln (1) : x = 2, x = - \frac{1}{2}

x = 2, x = - \frac{1}{2}

e^{2 x} + 3 x = 4

1 6^{x + 3} = 6 4^{2 x - 5}

3 e^{4 t} = 200

so l v e f or y, x = e^{- y^{2}}

4 e^{4 - x} = 5