8^{2x+3}=2^ab^x

Lösung

8^{2 x + 3} = 2^{a} b^{x}

x = \frac{ln ( 2 ) a - 9 ln ( 2 )}{6 ln ( 2 ) - ln ( b )}

Schritte zur Lösung

8^{2 x + 3} = 2^{a} b^{x}

Wende Exponentenregel an

3 (2 x + 3) ln (2) = ln (2^{a}) + x ln (b)

Löse

3 (2 x + 3) ln (2) = ln (2^{a}) + x ln (b) : x = \frac{ln ( 2 ) a - 9 ln ( 2 )}{6 ln ( 2 ) - ln ( b )}

x = \frac{ln ( 2 ) a - 9 ln ( 2 )}{6 ln ( 2 ) - ln ( b )}

e^{5 l n (x)} = 32

(5)^{3 x - 1} = 4

2^{3 x} = 7

3^{x} = e

0. 5^{\frac{x}{10}} = \frac{1}{8}