3^{2x+1}=5

Lösung

3^{2 x + 1} = 5

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

Dezimale

x = 0.23248 \dots

Schritte zur Lösung

3^{2 x + 1} = 5

Wende Exponentenregel an

(2 x + 1) ln (3) = ln (5)

Löse

(2 x + 1) ln (3) = ln (5) : x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 )}

so l v e f or x, 2^{x + y} = 8

97 \cdot 2^{2 x} = 69

3^{9 x} = 3^{7 x + 8}

2000 = 4000 e^{- 0.1 x}

2^{x} + \frac{1}{2 ^{x - 2}} = 5