3^{3+x}=7

Lösung

3^{3 + x} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} - 3

Dezimale

x = - 1.22875 \dots

Schritte zur Lösung

3^{3 + x} = 7

Wende Exponentenregel an

(3 + x) ln (3) = ln (7)

Löse

(3 + x) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} - 3

x = \frac{ln ( 7 )}{ln ( 3 )} - 3

- 2 = \frac{2 π}{( e ^{- c} + 1 )}

4^{- 2 x - 1} = 16

3^{(- x + 1)} = \frac{1}{81}

e^{2 z} + e^{z} + 1 = 0

2^{11 x} = 2^{x - 4}