2^{x-1}=3^{2x+1}

Lösung

2^{x - 1} = 3^{2 x + 1}

x = \frac{ln ( 6 )}{ln ( 2 ) - 2 ln ( 3 )}

Dezimale

x = - 1.19126 \dots

Schritte zur Lösung

2^{x - 1} = 3^{2 x + 1}

Wende Exponentenregel an

(x - 1) ln (2) = (2 x + 1) ln (3)

Löse

(x - 1) ln (2) = (2 x + 1) ln (3) : x = \frac{ln ( 6 )}{ln ( 2 ) - 2 ln ( 3 )}

x = \frac{ln ( 6 )}{ln ( 2 ) - 2 ln ( 3 )}

\frac{5 ^{2 x} - 1}{5 ^{x} + 1} = 4

8^{1 - 2 x} = 16

4 e^{3 x} - 7 = 1

(e^{4})^{3 x} = e^{4} e^{3 x}

4^{x} + 2^{x + 3} = 128