10^{2x+1}=4*10^x

Lösung

1 0^{2 x + 1} = 4 \cdot 1 0^{x}

x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

Dezimale

x = - 0.39794 \dots

Schritte zur Lösung

1 0^{2 x + 1} = 4 \cdot 1 0^{x}

Wende Exponentenregel an

(2 x + 1) ln (10) = ln (4) + x ln (10)

Löse

(2 x + 1) ln (10) = ln (4) + x ln (10) : x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

x = \frac{ln ( \frac{2}{5} )}{ln ( 10 )}

2^{x} + 2^{x} = 4

4^{5 - 3 x} = \frac{1}{8 ^{x + 1}}

4 \cdot 3^{x - 2} - 1 = 19

8^{n - 1} = 2

(x - 3)^{2 x - 4} = (x - 3)^{x + 3}