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受欢迎的代数 >

5(2^{2p+1})-17(2^{p+3})=0

解答

5 (2^{2 p + 1}) - 17 (2^{p + 3}) = 0

解答

p = \frac{ln ( \frac{68}{5} )}{ln ( 2 )}

+1

十进制

p = 3.76553 \dots

求解步骤

5 (2^{2 p + 1}) - 17 (2^{p + 3}) = 0

两边加上

17 \cdot 2^{p + 3}

5 \cdot 2^{2 p + 1} - 17 \cdot 2^{p + 3} + 17 \cdot 2^{p + 3} = 0 + 17 \cdot 2^{p + 3}

化简

5 \cdot 2^{2 p + 1} = 17 \cdot 2^{p + 3}

使用指数运算法则

ln (5) + (2 p + 1) ln (2) = ln (17) + (p + 3) ln (2)

解

ln (5) + (2 p + 1) ln (2) = ln (17) + (p + 3) ln (2) : p = \frac{ln ( \frac{68}{5} )}{ln ( 2 )}

p = \frac{ln ( \frac{68}{5} )}{ln ( 2 )}

作图

流行的例子

2048 = 4 \cdot 2^{x}

2^{2x-1}-5*2^{x-1}+2=0

2^{2 x - 1} - 5 \cdot 2^{x - 1} + 2 = 0

(5/3)^{4x-12}=1

(\frac{5}{3})^{4 x - 12} = 1

g (4) = 3 e^{t} - 2 t

2019.54 = 73 5^{n}