7^{x-1}=e^x

Lösung

7^{x - 1} = e^{x}

x = \frac{ln ( 7 )}{ln ( 7 ) - 1}

Dezimale

x = 2.05718 \dots

Schritte zur Lösung

7^{x - 1} = e^{x}

Wende Exponentenregel an

(x - 1) ln (7) = x

Löse

(x - 1) ln (7) = x : x = \frac{ln ( 7 )}{ln ( 7 ) - 1}

x = \frac{ln ( 7 )}{ln ( 7 ) - 1}

e^{7 n - 1} = 46

2^{300} + 2^{300} = 2^{x}

4 \cdot 3^{2 x} = 5^{x}

125 = 2 5^{x + 3}

3^{x + 1} = \frac{1 ^{x}}{3}