faktorisieren x^{11}+y^{11}

Lösung

faktorisieren

x^{11} + y^{11}

(x + y) (x^{10} - x^{9} y + x^{8} y^{2} - x^{7} y^{3} + x^{6} y^{4} - x^{5} y^{5} + x^{4} y^{6} - x^{3} y^{7} + x^{2} y^{8} - x y^{9} + y^{10})

Schritte zur Lösung

x^{11} + y^{11}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1}), n i s o dd

x^{11} + y^{11} = (x + y) (x^{10} - x^{9} y + x^{8} y^{2} - x^{7} y^{3} + x^{6} y^{4} - x^{5} y^{5} + x^{4} y^{6} - x^{3} y^{7} + x^{2} y^{8} - x y^{9} + y^{10})

= (x + y) (x^{10} - x^{9} y + x^{8} y^{2} - x^{7} y^{3} + x^{6} y^{4} - x^{5} y^{5} + x^{4} y^{6} - x^{3} y^{7} + x^{2} y^{8} - x y^{9} + y^{10})

f a c t or 5 x^{2} - 10 x - 15

f a c t or 2 x^{2} + 5 x + 2

s im pl i f y \frac{2 \cdot 27}{( 0.075 ) ^{2}}

- 2 < x \leq \frac{16}{3}

f a c t or x^{3} - 2 x + 4