solvefor t,w(t)=sqrt(t-9)

Lösung

löse nach

t, w (t) = t - 9

t = \frac{1 + 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}, t = \frac{1 - 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}

Schritte zur Lösung

w (t) = t - 9

Quadriere beide Seiten:

t^{2} w^{2} = t - 9

t^{2} w^{2} = t - 9

Löse

t^{2} w^{2} = t - 9 : t = \frac{1 + 1 - 36 w ^{2}}{2 w ^{2}}, t = \frac{1 - 1 - 36 w ^{2}}{2 w ^{2}}

t = \frac{1 + 1 - 36 w ^{2}}{2 w ^{2}}, t = \frac{1 - 1 - 36 w ^{2}}{2 w ^{2}}

Überprüfe die Lösungen:

t = \frac{1 + 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}, t = \frac{1 - 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}

Die Lösungen sind

t = \frac{1 + 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}, t = \frac{1 - 1 - 36 w ^{2}}{2 w ^{2}} {0 < w \leq \frac{1}{6}}

(x + 3)^{\frac{3}{2}} = 27

x - 5 = x + 10

4 2 x - 6 = 2

x = 2 x 100 - x^{2}

4 x + 1 - 2 = x