5a^2-11|a|+2=0

解

5 a^{2} - 11 ∣ a ∣ + 2 = 0

a = - 2 or a = - \frac{1}{5} or a = \frac{1}{5} or a = 2

十進法表記

a = - 2, a = - 0.2, a = 0.2, a = 2

解答ステップ

5 a^{2} - 11 ∣ a ∣ + 2 = 0

正と負の区間を求める

a < 0, a \geq 0

各区間の不等式を解く

(a = - 2 or a = - \frac{1}{5}) or (a = \frac{1}{5} or a = 2)

a = - 2 or a = - \frac{1}{5} or a = \frac{1}{5} or a = 2