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受欢迎的代数 >

solvefor x,xsin(y)-x^2y^{-3}=c

解答

求解

x, x sin (y) - x^{2} y^{- 3} = c

解答

x = - \frac{y ^{3} ( - sin ( y ) + \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}, x = - \frac{y ^{3} ( - sin ( y ) - \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}

求解步骤

x sin (y) - x^{2} y^{- 3} = c

展开

x sin (y) - x^{2} y^{- 3} : x sin (y) - \frac{x ^{2}}{y ^{3}}

x sin (y) - \frac{x ^{2}}{y ^{3}} = c

将

c

para o lado esquerdo

x sin (y) - \frac{x ^{2}}{y ^{3}} - c = 0

改写成标准形式

a x^{2} + b x + c = 0

- \frac{x ^{2}}{y ^{3}} + sin (y) x - c = 0

使用求根公式求解

x_{1, 2} = \frac{- sin ( y ) \pm ( sin ( y ) ) ^{2} - 4 ( - \frac{1}{y ^{3}} ) ( - c )}{2 ( - \frac{1}{y ^{3}} )}

化简

(sin (y))^{2} - 4 (- \frac{1}{y ^{3}}) (- c) : \frac{y ^{3} sin ^{2} ( y ) - 4 c}{y ^{3}}

x_{1, 2} = \frac{- sin ( y ) \pm \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}}}{2 ( - \frac{1}{y ^{3}} )}

将解分隔开

x_{1} = \frac{- sin ( y ) + \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}}}{2 ( - \frac{1}{y ^{3}} )}, x_{2} = \frac{- sin ( y ) - \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}}}{2 ( - \frac{1}{y ^{3}} )}

x = \frac{- sin ( y ) + \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}}}{2 ( - \frac{1}{y ^{3}} )} : - \frac{y ^{3} ( - sin ( y ) + \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}

x = \frac{- sin ( y ) - \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}}}{2 ( - \frac{1}{y ^{3}} )} : - \frac{y ^{3} ( - sin ( y ) - \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}

二次方程组的解是:

x = - \frac{y ^{3} ( - sin ( y ) + \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}, x = - \frac{y ^{3} ( - sin ( y ) - \frac{y ^{3} s i n ^{2} ( y ) - 4 c}{y ^{3}} )}{2}

作图

流行的例子

z^{2} = - 3 - 4 i

(a + 6) + 2 bi = 6 - 5 i

((1-i)/(1+i))^{100}=a+ib

(\frac{1 - i}{1 + i})^{100} = a + ib

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z^{2} - 4 i z - 1 = 0