15-28=3l+(4m)i

解答

15 - 28 = 3 l + (4 m) i

l = - \frac{13}{3}, m = 0

求解步骤

15 - 28 = 3 l + (4 m) i

将

15 - 28

改写成标准复数形式:

(15 - 28) + 0 i

(15 - 28) + 0 i = 3 l + (4 m) i

将

3 l + (4 m) i

改写成标准复数形式:

3 l + 4 mi

(15 - 28) + 0 i = 3 l + 4 mi

复数仅在实部和虚部均相等时才相等改写为方程组:

[15 - 28 = 3 l 0 = 4 m]

[15 - 28 = 3 l 0 = 4 m] : l = - \frac{13}{3}, m = 0

l = - \frac{13}{3}, m = 0

+ 4 i z^{2} = 2 + 2 i, z^{1} = 7

\frac{2 + ai}{7 + bi} = 3 + 6 i

4 x + i (5 x - y) = 2 + i (- 3)

so l v e f or x, \frac{x}{1 - x} = 1 - 5 i

(x - y i) + ∣ x + y i ∣ = 25 - 5 i