sif(x)=2-3x^2

解

s i f (x) = 2 - 3 x^{2}

s = 0, s \in R, s = 0, s \in R, s = 0, s = 0, s \in R, s \in R, x = - \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, f \in R f = 0 f \in R f = 0 f \in R f \in R f = 0 f = 0

解答ステップ

s i f (x) = 2 - 3 x^{2}

標準的な複素数形式で

s i f (x)

を書き換える:

0 + s f (x) i

0 + s f (x) i = 2 - 3 x^{2}

標準的な複素数形式で

2 - 3 x^{2}

を書き換える:

(2 - 3 x^{2}) + 0 i

0 + s f (x) i = (2 - 3 x^{2}) + 0 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[0 = 2 - 3 x^{2} s f (x) = 0]

[0 = 2 - 3 x^{2} s f (x) = 0] : s = 0, s \in R, s = 0, s \in R, s = 0, s = 0, s \in R, s \in R, x = - \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, f \in R f = 0 f \in R f = 0 f \in R f \in R f = 0 f = 0

s = 0, s \in R, s = 0, s \in R, s = 0, s = 0, s \in R, s \in R, x = - \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, x = \frac{2}{3}, x = - \frac{2}{3}, f \in R f = 0 f \in R f = 0 f \in R f \in R f = 0 f = 0