2^{x+1}=5

Lösung

2^{x + 1} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} - 1

Dezimale

x = 1.32192 \dots

Schritte zur Lösung

2^{x + 1} = 5

Wende Exponentenregel an

(x + 1) ln (2) = ln (5)

Löse

(x + 1) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} - 1

x = \frac{ln ( 5 )}{ln ( 2 )} - 1

4^{2 x - 3} = 8^{x + 4}

so l v e f or n, (1 - p)^{n} = \frac{1}{2}

3 6^{x} \cdot 6^{x^{2}} = 129 6^{2}

e^{5 x} = 0

so l v e f or y, e^{x y} = y