32^x=(1/128)^{x-8}

Lösung

3 2^{x} = (\frac{1}{128})^{x - 8}

x = \frac{14}{3}

Dezimale

x = 4.66666 \dots

Schritte zur Lösung

3 2^{x} = (\frac{1}{128})^{x - 8}

Wende Exponentenregel an

5 x = - 7 (x - 8)

Löse

5 x = - 7 (x - 8) : x = \frac{14}{3}

x = \frac{14}{3}

2^{4 - 2 x} = 64

so l v e f or y, y^{x} = x^{y}

9^{x - 2} + 3^{x + 1} = 90

ln (5^{x} - 1) = 3

2 5^{2 x + 4} = 62 5^{2 x - 1}