10^{7-x}=5^{x+1}

Lösung

1 0^{7 - x} = 5^{x + 1}

x = \frac{ln ( 2000000 )}{ln ( 50 )}

Dezimale

x = 3.70873 \dots

Schritte zur Lösung

1 0^{7 - x} = 5^{x + 1}

Wende Exponentenregel an

(7 - x) ln (10) = (x + 1) ln (5)

Löse

(7 - x) ln (10) = (x + 1) ln (5) : x = \frac{ln ( 2000000 )}{ln ( 50 )}

x = \frac{ln ( 2000000 )}{ln ( 50 )}

2^{x} + 8^{x} = 130

4^{- 2 x} = 7

2^{6 x} = 0.125

1 6^{x} = x^{8}

4^{2 x} = 4^{- 2 x - 1}