(1.012^{t-1998})=1.1707

Lösung

(1.01 2^{t - 1998}) = 1.1707

t = \frac{ln ( 1.1707 )}{ln ( 1.012 )} + 1998

Dezimale

t = 2011.21213 \dots

Schritte zur Lösung

(1.01 2^{t - 1998}) = 1.1707

Wende Exponentenregel an

(t - 1998) ln (1.012) = ln (1.1707)

Löse

(t - 1998) ln (1.012) = ln (1.1707) : t = \frac{ln ( 1.1707 )}{ln ( 1.012 )} + 1998

t = \frac{ln ( 1.1707 )}{ln ( 1.012 )} + 1998

2^{4 x - 2} = 4^{x + 2}

5^{3 x + 8} = 2 5^{2 x}

0.0 1^{x} = 100

\frac{1}{3} e^{3 t} = \frac{1}{2}

\frac{e ^{x}}{1 + e ^{x}} = 0.5