16^{2x+1}=4^{3x+3}

Lösung

1 6^{2 x + 1} = 4^{3 x + 3}

x = 1

Schritte zur Lösung

1 6^{2 x + 1} = 4^{3 x + 3}

Wende Exponentenregel an

2 (2 x + 1) = 3 x + 3

Löse

2 (2 x + 1) = 3 x + 3 : x = 1

x = 1

so l v e f or y, e^{x + y} = 0

312 5^{x - 1} = 62 5^{2 x - 2}

\frac{4 ^{x}}{3 ^{x}} = \frac{9}{16}

6 4^{- x + 39} = 12 8^{x}

1 7^{x} = 4.7