2^{-b}=1

Lösung

2^{- b} = 1

b = 0

Schritte zur Lösung

2^{- b} = 1

Wende Exponentenregel an

- b ln (2) = ln (1)

Löse

- b ln (2) = ln (1) : b = 0

b = 0

5^{5 - x} = \frac{1}{25}

so l v e f or x, 312 5^{x + 4} = 2 5^{2 x}

7^{y} = 15

3^{2 x} - 3 (3^{x}) = 4

3^{x + 1} = 9^{x - 2}