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人気のある代数 >

solvefor y,x^{2/3}+y^{2/3}=1

解

解く

y, x^{\frac{2}{3}} + y^{\frac{2}{3}} = 1

解

y = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}, y = - 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}

解答ステップ

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 1

x^{\frac{2}{3}}

を右側に移動します

y^{\frac{2}{3}} = 1 - x^{\frac{2}{3}}

equationの両辺を以下の累乗にする:

3 : y^{2} = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}

y^{2} = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}

解く

y^{2} = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} : y = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}, y = - 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}

y = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}, y = - 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2}

解を検算する:

y = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}, y = - 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}

解答は

y = 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}, y = - 1 - 3 x^{\frac{2}{3}} + 3 x^{\frac{4}{3}} - x^{2} {- 1 \leq x \leq 1}

グラフ

人気の例

solvefor y,x=sqrt(4-y^2)

so l v e f or y, x = 4 - y^{2}

sqrt(2x-6)-sqrt(x-5)=sqrt(x-1)

2 x - 6 - x - 5 = x - 1

2sqrt(x+8)=3sqrt(x-2)

2 x + 8 = 3 x - 2

2 x + 8 = - 5

-6+sqrt(x+10)=2

- 6 + x + 10 = 2