|x^2+4x-5|=7

Lösung

x^{2} + 4 x - 5 = 7

x = - 6 or x = - 2 - 2 or x = - 2 + 2 or x = 2

Dezimale

x = - 6, x = - 3.41421 \dots, x = - 0.58578 \dots, x = 2

Schritte zur Lösung

x^{2} + 4 x - 5 = 7

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 4 x - 5 = - 7 or x^{2} + 4 x - 5 = 7

x^{2} + 4 x - 5 = - 7 or x^{2} + 4 x - 5 = 7

(x = - 2 - 2 or x = - 2 + 2) or (x = - 6 or x = 2)

x = - 6 or x = - 2 - 2 or x = - 2 + 2 or x = 2

x^{2} - 6 = ∣ 5 x ∣

∣ 3 x - 8 ∣ - ∣ 3 x - 2 ∣ = 6

∣ 3 - 3 x ∣ = 5

so l v e f or y, ∣ x + y ∣ = 1

∣ 2 x ∣ = 84