quadraticformula x^2-12x+35=0

解

x^{2} - 12 x + 35 = 0

x = 7, x = 5

解答ステップ

x^{2} - 12 x + 35 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

x = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

二次equationの解:

x = 7, x = 5