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受欢迎的代数 >

solvefor n,n*0.11(n-1)+35=3n

解答

求解

n, n \cdot 0.11 (n - 1) + 35 = 3 n

解答

n = \frac{311}{22} + i \frac{57279}{22}, n = \frac{311}{22} - i \frac{57279}{22}

求解步骤

n \cdot 0.11 (n - 1) + 35 = 3 n

在两边乘以

100

11 n (n - 1) + 3500 = 300 n

展开

11 n (n - 1) + 3500 : 11 n^{2} - 11 n + 3500

11 n^{2} - 11 n + 3500 = 300 n

将

300 n

para o lado esquerdo

11 n^{2} - 311 n + 3500 = 0

使用求根公式求解

n_{1, 2} = \frac{- ( - 311 ) \pm ( - 311 ) ^{2} - 4 \cdot 11 \cdot 3500}{2 \cdot 11}

化简

(- 311)^{2} - 4 \cdot 11 \cdot 3500 : 57279 i

n_{1, 2} = \frac{- ( - 311 ) \pm 57279 i}{2 \cdot 11}

将解分隔开

n_{1} = \frac{- ( - 311 ) + 57279 i}{2 \cdot 11}, n_{2} = \frac{- ( - 311 ) - 57279 i}{2 \cdot 11}

n = \frac{- ( - 311 ) + 57279 i}{2 \cdot 11} : \frac{311}{22} + i \frac{57279}{22}

n = \frac{- ( - 311 ) - 57279 i}{2 \cdot 11} : \frac{311}{22} - i \frac{57279}{22}

二次方程组的解是:

n = \frac{311}{22} + i \frac{57279}{22}, n = \frac{311}{22} - i \frac{57279}{22}

作图

流行的例子

化简 ((sqrt(200)))/((sqrt(5)))

s im pl i f y \frac{( 200 )}{( 5 )}

因式分解 9x^3+18x^2-4x-8

f a c t or 9 x^{3} + 18 x^{2} - 4 x - 8

s im pl i f y 8.25%

s im pl i f y 5.4%

solvefor x,2x+4=24

so l v e f or x, 2 x + 4 = 24