因式分解 36x^2+12x+1

解答

因式分解

36 x^{2} + 12 x + 1

(6 x + 1)^{2}

求解步骤

36 x^{2} + 12 x + 1

改写为形式

a^{2} + 2 ab + b^{2} :

36 x^{2} = (6 x)^{2}

1 = 1^{2}

12 x = 2 \cdot 6 x \cdot 1

= (6 x)^{2} + 2 \cdot 6 x \cdot 1 + 1^{2}

使用完全平方公式:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(6 x)^{2} + 2 \cdot 6 x \cdot 1 + 1^{2} = (6 x + 1)^{2}

= (6 x + 1)^{2}

\frac{∣ 0.5 + 1 ∣}{0.5 + 1} > \frac{1}{0.5 - 1}

- 2 w (w + 9) = 0

\frac{2}{3} (3 x + 6) = 4 x + 3

\frac{4}{2 - x} \geq \frac{3}{1 - x}

\frac{1}{10} + 2 x + \frac{3}{20} + 2 x^{2} + \frac{x}{2} = 1