w^2-10w+25=0

解

w^{2} - 10 w + 25 = 0

w = 5

解答ステップ

w^{2} - 10 w + 25 = 0

解くとthe二次式

w_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

w_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

w = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

w = 5

二次equationの解:

w = 5