8n>= 7n-3

解答

8 n \geq 7 n - 3

n \geq - 3

间隔符号

[- 3, \infty)

求解步骤

8 n \geq 7 n - 3

将

7 n

para o lado esquerdo

n \geq - 3

- 16 \leq - 2 x - 6

- \frac{3}{4} (x - \frac{1}{2})^{2} + 9 = 0

f a c t or 12 x^{3} - 31 x^{2} + 20 x

f a c t or lo g_{5} (3 x + 6 y)

- 5 = 2 x - 3