2x^2+12x+16=0

解

2 x^{2} + 12 x + 16 = 0

x = - 2, x = - 4

解答ステップ

2 x^{2} + 12 x + 16 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 16}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 16 = 4

x_{1, 2} = \frac{- 12 \pm 4}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 12 + 4}{2 \cdot 2}, x_{2} = \frac{- 12 - 4}{2 \cdot 2}

x = \frac{- 12 + 4}{2 \cdot 2} : - 2

x = \frac{- 12 - 4}{2 \cdot 2} : - 4

二次equationの解:

x = - 2, x = - 4