|x|<= 6

Lösung

∣ x ∣ \leq 6

- 6 \leq x \leq 6

Intervall-Notation

[- 6, 6]

Schritte zur Lösung

∣ x ∣ \leq 6

Wende Absoluteregel an: Wenn

∣ u ∣ \leq a, a > 0

dann

- a \leq u \leq a

- 6 \leq x \leq 6

x + 8 > 5

- 4.9 x^{2} + 10 x + 30 = 0

2^{2} + 8^{2} = c^{2}

(x - 1)^{2} = 7

f a c t or x^{2} + 8 x y + 16 y^{2}