化简 |8-9|

解答

化简

∣ 8 - 9 ∣

1

求解步骤

∣ 8 - 9 ∣

数字相减:

8 - 9 = - 1

= ∣ - 1 ∣

使用绝对值运算法则:

∣ - a ∣ = a, a > 0

= 1

\frac{∣ x - 1 ∣}{x} + \frac{x + 2}{x - 1} \geq 1

s im pl i f y (\frac{3 ( x - 12 ) ^{\frac{1}{2}}}{2})^{2}

1 + x^{2} = 0

f a c t or 2 x^{3} + 17 x^{2} + 46 x + 40

\frac{3 x - 7 ( x + 1 )}{6} = \frac{2 x - 1}{3} - 2