x^2+16x+28=0

解

x^{2} + 16 x + 28 = 0

x = - 2, x = - 14

解答ステップ

x^{2} + 16 x + 28 = 0

解くとthe二次式

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 28 = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 16 + 12}{2 \cdot 1}, x_{2} = \frac{- 16 - 12}{2 \cdot 1}

x = \frac{- 16 + 12}{2 \cdot 1} : - 2

x = \frac{- 16 - 12}{2 \cdot 1} : - 14

二次equationの解:

x = - 2, x = - 14