x^2+7x+10>= 0

Lösung

x^{2} + 7 x + 10 \geq 0

x \leq - 5 or x \geq - 2

Intervall-Notation

(- \infty, - 5] \cup [- 2, \infty)

Schritte zur Lösung

x^{2} + 7 x + 10 \geq 0

Faktorisiere

x^{2} + 7 x + 10 : (x + 2) (x + 5)

(x + 2) (x + 5) \geq 0

Identifiziere die Intervalle

x \leq - 5 or x \geq - 2

x - 1 > 6

80 = (x - 6) (x - 6) (3)

(m + 4)^{2} = 0

3 x^{2} - 11 x - 14 = 0

s im pl i f y - 1 + \frac{7}{2}