因式分解 4x^2+4xy+y^2

解答

因式分解

4 x^{2} + 4 x y + y^{2}

(2 x + y)^{2}

求解步骤

4 x^{2} + 4 x y + y^{2}

改写为形式

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

4 x y = 2 \cdot 2 x y

= (2 x)^{2} + 2 \cdot 2 x y + y^{2}

使用完全平方公式:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 x)^{2} + 2 \cdot 2 x y + y^{2} = (2 x + y)^{2}

= (2 x + y)^{2}

x^{2} - 5 x - 36 = 0

3 + 5 e = 8 (6 - 7 e)

f a c t or - x^{2} - 77 x + 78

f a c t or 2 x^{3} - 4 x^{2} - 34 x + 68

f a c t or x^{4} - 7 x^{3} + 6 x^{2} + 19 x + 5