18m^2+12m+1997=0

解

18 m^{2} + 12 m + 1997 = 0

m = - \frac{1}{3} + i \frac{665}{6}, m = - \frac{1}{3} - i \frac{665}{6}

解答ステップ

18 m^{2} + 12 m + 1997 = 0

解くとthe二次式

m_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 18 \cdot 1997}{2 \cdot 18}

簡素化

1 2^{2} - 4 \cdot 18 \cdot 1997 : 63990 i

m_{1, 2} = \frac{- 12 \pm 6 3990 i}{2 \cdot 18}

解を分離する

m_{1} = \frac{- 12 + 6 3990 i}{2 \cdot 18}, m_{2} = \frac{- 12 - 6 3990 i}{2 \cdot 18}

m = \frac{- 12 + 6 3990 i}{2 \cdot 18} : - \frac{1}{3} + i \frac{665}{6}

m = \frac{- 12 - 6 3990 i}{2 \cdot 18} : - \frac{1}{3} - i \frac{665}{6}

二次equationの解:

m = - \frac{1}{3} + i \frac{665}{6}, m = - \frac{1}{3} - i \frac{665}{6}