vereinfachen (64a^2b^{-3/4})^{1/2}

Lösung

vereinfachen

(64 a^{2} b^{- \frac{3}{4}})^{\frac{1}{2}}

\frac{8 a}{b ^{\frac{3}{8}}}

Schritte zur Lösung

(64 a^{2} b^{- \frac{3}{4}})^{\frac{1}{2}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(64 a^{2} b^{- \frac{3}{4}})^{\frac{1}{2}} = 6 4^{\frac{1}{2}} (a^{2})^{\frac{1}{2}} (b^{- \frac{3}{4}})^{\frac{1}{2}}

= 6 4^{\frac{1}{2}} (a^{2})^{\frac{1}{2}} (b^{- \frac{3}{4}})^{\frac{1}{2}}

6 4^{\frac{1}{2}} = 8

= 8 (a^{2})^{\frac{1}{2}} (b^{- \frac{3}{4}})^{\frac{1}{2}}

Vereinfache

(a^{2})^{\frac{1}{2}} : a

= 8 a (b^{- \frac{3}{4}})^{\frac{1}{2}}

Vereinfache

(b^{- \frac{3}{4}})^{\frac{1}{2}} : \frac{1}{b ^{\frac{3}{8}}}

= 8 a \frac{1}{b ^{\frac{3}{8}}}

Vereinfache

8 a \frac{1}{b ^{\frac{3}{8}}} : \frac{8 a}{b ^{\frac{3}{8}}}

= \frac{8 a}{b ^{\frac{3}{8}}}

4 x - 5 > 3

f a c t or 6 x^{2} - 21 x

- 1 = 2 x + \frac{7}{3}

m - (- 2) < 17

f a c t or z^{2} - 4 z - 21