y^{''}+4y^'+5y=-20e^t,y(0)=-4,y^'(0)=1

Lösung

y^{^{''}} + 4 y^{^{'}} + 5 y = - 20 e^{t}, y (0) = - 4, y^{^{'}} (0) = 1

y = e^{- 2 t} (- 2 cos (t) - sin (t)) - 2 e^{t}

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + 5 y = - 20 e^{t}

Solve linear ODE:

y = e^{- 2 t} (- 2 cos (t) - sin (t)) - 2 e^{t}

y = e^{- 2 t} (- 2 cos (t) - sin (t)) - 2 e^{t}

\int_{1}^{4} 6 e^{x} d x

cr i t i c a l f (x, y) = (x)^{2} + (y)^{4}

x \to 3 + lim (\frac{1}{∣ x - 3 ∣})

y \to 0 lim (\frac{y ^{2}}{y ^{4}})

d er i v a t i v e f (x) = e^{x} - x^{7}