integral from-1 to 2 of (-x^2+x+2)

Lösung

\int_{- 1}^{2} (- x^{2} + x + 2) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{- 1}^{2} - x^{2} + x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} x^{2} d x + \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

= - 3 + \frac{3}{2} + 6

Vereinfache

- 3 + \frac{3}{2} + 6 : \frac{9}{2}

= \frac{9}{2}

\frac{d}{d x} (tan (x^{3}))

d er i v a t i v e \frac{sin ^{2} ( x )}{cos ^{2} ( x )}

x \to 4 + lim (2 x - 7)

s l o p e x + \frac{1}{x ^{3}}

\int (\frac{x - 2}{x ( x ^{2} + 2 )}) d x