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Beliebt Rechnen >

1/t y^'= y/(t^2)-1/y

Lösung

\frac{1}{t} y^{^{'}} = \frac{y}{t ^{2}} - \frac{1}{y}

Lösung

y = t - 2 ln (t) + c_{1}, y = - t - 2 ln (t) + c_{1}

Schritte zur Lösung

\frac{1}{t} y^{'} (t) = \frac{y}{t ^{2}} - \frac{1}{y}

Solve Bernoulli ODE:

y = t - 2 ln (t) + c_{1}, y = - t - 2 ln (t) + c_{1}

y = t - 2 ln (t) + c_{1}, y = - t - 2 ln (t) + c_{1}

Graph

Beliebte Beispiele

(\partial)/(\partial y)(5y-2x)

2y^{''}+8y^'+80y=100cos(8t)

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