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人気のある微分積分 >

integral of tan^8(x)sec^4(x)

解

\int tan^{8} (x) sec^{4} (x) d x

解

\frac{tan ^{9} ( x )}{9} + \frac{tan ^{11} ( x )}{11} + C

解答ステップ

\int tan^{8} (x) sec^{4} (x) d x

三角関数の公式を使用して書き換える

= \int (1 + tan^{2} (x)) sec^{2} (x) tan^{8} (x) d x

u置換積分法を適用する

= \int u^{8} (1 + u^{2}) d u

拡張

u^{8} (1 + u^{2}) : u^{8} + u^{10}

= \int u^{8} + u^{10} d u

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{8} d u + \int u^{10} d u

\int u^{8} d u = \frac{u ^{9}}{9}

\int u^{10} d u = \frac{u ^{11}}{11}

= \frac{u ^{9}}{9} + \frac{u ^{11}}{11}

代用を戻す

u = tan (x)

= \frac{tan ^{9} ( x )}{9} + \frac{tan ^{11} ( x )}{11}

定数を解答に追加する

= \frac{tan ^{9} ( x )}{9} + \frac{tan ^{11} ( x )}{11} + C

グラフ

人気の例

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