What is the tangent of y=2sin(x),\at x= 3/4 pi ?

The tangent of y=2sin(x),\at x= 3/4 pi is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))

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tangent of y=2sin(x),\at x= 3/4 pi

tangent of

y = 2 sin (x), at x = \frac{3}{4} π

y = - 2 x + 2 + \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, 2)

Find the slope of

y = 2 sin (x) : \frac{d y}{d x} = 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{3}{4} π, 2) : y = - 2 x + 2 + \frac{3 π}{2 2}

y = - 2 x + 2 + \frac{3 π}{2 2}

What is the tangent of y=2sin(x),\at x= 3/4 pi ?
The tangent of y=2sin(x),\at x= 3/4 pi is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))