derivative of-2(2x^2-4x-1^2)

Lösung

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

- 4 (2 x^{2} - 4 x - 1) (4 x - 4)

Schritte zur Lösung

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} ((2 x^{2} - 4 x - 1)^{2})

Wende die Kettenregel an:

2 (2 x^{2} - 4 x - 1) \frac{d}{d x} (2 x^{2} - 4 x - 1)

= 2 (2 x^{2} - 4 x - 1) \frac{d}{d x} (2 x^{2} - 4 x - 1)

\frac{d}{d x} (2 x^{2} - 4 x - 1) = 4 x - 4

= - 2 \cdot 2 (2 x^{2} - 4 x - 1) (4 x - 4)

Vereinfache

= - 4 (2 x^{2} - 4 x - 1) (4 x - 4)

\frac{\partial}{\partial x} (2)

t \cdot y^{^{'}} + 4 y = 8 t

y^{^{''}} + 3 y^{^{'}} - 4 y = e^{- 4 x} + x e^{- x}

\frac{\partial}{\partial x} (z^{x y^{2}})

x \to 0 + lim (\frac{x - ∣ x ∣}{∣ x ∣})