What is the derivative of f(x)=-3x^2+24x-36 ?

The derivative of f(x)=-3x^2+24x-36 is -6x+24

What is the first derivative of f(x)=-3x^2+24x-36 ?

The first derivative of f(x)=-3x^2+24x-36 is -6x+24

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derivative of

f (x) = - 3 x^{2} + 24 x - 36

- 6 x + 24

Solution steps

\frac{d}{d x} (- 3 x^{2} + 24 x - 36)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (24 x) - \frac{d}{d x} (36)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (24 x) = 24

\frac{d}{d x} (36) = 0

= - 6 x + 24 - 0

Simplify

= - 6 x + 24

What is the derivative of f(x)=-3x^2+24x-36 ?
The derivative of f(x)=-3x^2+24x-36 is -6x+24
What is the first derivative of f(x)=-3x^2+24x-36 ?
The first derivative of f(x)=-3x^2+24x-36 is -6x+24