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人気のある微分積分 >

laplacetransform e^{2t}sin(j^2t)

解

ラプラス変換

e^{2 t} sin (j^{2} t)

解

\frac{j ^{2}}{( s - 2 ) ^{2} + j ^{4}}

解答ステップ

L {e^{2 t} sin (j^{2} t)}

変換ルールを適用:

L {f (t)} = F (s)

ならば

L {e^{a t} f (t)} = F (s - a)

e^{2 t} sin (j^{2} t)

向け

: f (t) = sin (j^{2} t), a = 2

= L {sin (j^{2} t)} (s - 2)

L {sin (j^{2} t)} : \frac{j ^{2}}{s ^{2} + j ^{4}}

= \frac{j ^{2}}{( s - 2 ) ^{2} + j ^{4}}

人気の例

(\partial)/(\partial x)((9+20x)y^{tan(x)})

\frac{\partial}{\partial x} ((9 + 20 x) y^{t a n (x)})

tangent f(x)=-x^2,(-3,-9)

t an g e n t f (x) = - x^{2}, (- 3, - 9)

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\int \frac{2}{( x - 2 ) ( x ^{4} + 4 )} d x

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x \to - \infty lim (- 3 - x)

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\int_{0}^{3} x^{2} + 16 d x